
رد : سؤال ... A
[(2 ×32×y3z(-3)t3)(-2)] ×[33x4y(-5)]2 = [(9x2+3)(4+4x+4x2)][(x-1)(2x+2)-2x2+2)].
= [(9x2+3)(4+4x+4x2)][(x-1)(2x+2)-2x2+2)]
z(-3)t3)(-2)] ×[33x4y(-5)]2 = [(9x2+3)(4+4x+4x2)][(x-1)(2x+2)-2x2+2)].
[(2 ×32×y3z(-3)t3)(-2)] ×[33x4y(-5)]2 = [(9x2+3)(4+4x+4x2)][(x-1)(2x+2)-2x2+2)].
حلها سهل